(x+2)(x^2+4*x+4)-8=0

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Solution for (x+2)(x^2+4*x+4)-8=0 equation:


Simplifying
(x + 2)(x2 + 4x + 4) + -8 = 0

Reorder the terms:
(2 + x)(x2 + 4x + 4) + -8 = 0

Reorder the terms:
(2 + x)(4 + 4x + x2) + -8 = 0

Multiply (2 + x) * (4 + 4x + x2)
(2(4 + 4x + x2) + x(4 + 4x + x2)) + -8 = 0
((4 * 2 + 4x * 2 + x2 * 2) + x(4 + 4x + x2)) + -8 = 0
((8 + 8x + 2x2) + x(4 + 4x + x2)) + -8 = 0
(8 + 8x + 2x2 + (4 * x + 4x * x + x2 * x)) + -8 = 0
(8 + 8x + 2x2 + (4x + 4x2 + x3)) + -8 = 0

Reorder the terms:
(8 + 8x + 4x + 2x2 + 4x2 + x3) + -8 = 0

Combine like terms: 8x + 4x = 12x
(8 + 12x + 2x2 + 4x2 + x3) + -8 = 0

Combine like terms: 2x2 + 4x2 = 6x2
(8 + 12x + 6x2 + x3) + -8 = 0

Reorder the terms:
8 + -8 + 12x + 6x2 + x3 = 0

Combine like terms: 8 + -8 = 0
0 + 12x + 6x2 + x3 = 0
12x + 6x2 + x3 = 0

Solving
12x + 6x2 + x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(12 + 6x + x2) = 0

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(12 + 6x + x2)' equal to zero and attempt to solve: Simplifying 12 + 6x + x2 = 0 Solving 12 + 6x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-12' to each side of the equation. 12 + 6x + -12 + x2 = 0 + -12 Reorder the terms: 12 + -12 + 6x + x2 = 0 + -12 Combine like terms: 12 + -12 = 0 0 + 6x + x2 = 0 + -12 6x + x2 = 0 + -12 Combine like terms: 0 + -12 = -12 6x + x2 = -12 The x term is 6x. Take half its coefficient (3). Square it (9) and add it to both sides. Add '9' to each side of the equation. 6x + 9 + x2 = -12 + 9 Reorder the terms: 9 + 6x + x2 = -12 + 9 Combine like terms: -12 + 9 = -3 9 + 6x + x2 = -3 Factor a perfect square on the left side: (x + 3)(x + 3) = -3 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

x = {0}

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